# Learn Advanced Array Methods by Building a Statistics Calculator - Step 22

### Tell us what’s happening:

I have a problem within my ternary operator I can´t do this step. Could someone please explain to me what I am doing wrong?

// User Editable Region

``````const getMedian = (array) => {
const sorted = array.sort((a, b) => a - b);
const median = array.length % 2 === 0 ? getMean(sorted.length / 2 + sorted.length / 2 - 1) : Math.floor(sorted.length / 2);
}
``````

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### Challenge Information:

Learn Advanced Array Methods by Building a Statistics Calculator - Step 22

What error message are you getting? Looking carefully at the exact wording of the error message can often help.

If `array.length` is even, pass an array with the two middle numbers from the `sorted` array to the `getMean` function. The first item in the array argument should be the value at index `array.length / 2` from `sorted` and the second should use the value at the index `array.length / 2 - 1` from `sorted` .

Right now you aren’t accessing the `value` of those indexes,rather you are sending the indexes themselves. How do you access the value at an index in an array?

Note the words “`sorted` array” - it wants an array passed in

const median = array.length % 2 === 0 ? getMean(sorted[array.length / 2], [array.length / 2 - 1]) : sorted[Math.floor(array.length / 2)];
I know that the getMean function receives an ordered array which is “sorted” but I can’t find a way to pass the data to sorted

You’re so close - remember that `sorted` is an array so all the ‘arguments’ to `sorted` should be arrays (you have 2 out of 3 there) but also that `getMean` is expecting an array

const median = array.length % 2 === 0 ? getMean(sorted[array.length / 2] , sorted[array.length / 2 - 1]): sorted[Math.floor(array.length / 2)];
I tried this logic but I don´t know if I’m broking more my code.

getMean takes only one argument–an array. Your code has two arguments in the getMean function.

Thanks for your advices! It’s working now