Learn Advanced Array Methods by Building a Statistics Calculator - Step 27

Tell us what’s happening:

I’m stuck here. I tried everything I could even chatGPT solutions - but the code doesn’t pass. Help me please

Your code so far

<!-- file: index.html -->
<!DOCTYPE html>
<html lang="en">
  <head>
    <meta charset="utf-8" />
    <meta name="viewport" content="width=device-width, initial-scale=1" />
    <link rel="stylesheet" href="./styles.css" />
    <script src="./script.js"></script>
    <title>Statistics Calculator</title>
  </head>
  <body>
    <h1>Statistics Calculator</h1>
    <p>Enter a list of comma-separated numbers.</p>
    <form onsubmit="calculate(); return false;">
      <label for="numbers">Numbers:</label>
      <input type="text" name="numbers" id="numbers" />
      <button type="submit">Calculate</button>
    </form>
    <div class="results">
      <p>
        The <dfn>mean</dfn> of a list of numbers is the average, calculated by
        taking the sum of all numbers and dividing that by the count of numbers.
      </p>
      <p class="bold">Mean: <span id="mean"></span></p>
      <p>
        The <dfn>median</dfn> of a list of numbers is the number that appears in
        the middle of the list, when sorted from least to greatest.
      </p>
      <p class="bold">Median: <span id="median"></span></p>
      <p>
        The <dfn>mode</dfn> of a list of numbers is the number that appears most
        often in the list.
      </p>
      <p class="bold">Mode: <span id="mode"></span></p>
      <p>
        The <dfn>range</dfn> of a list of numbers is the difference between the
        largest and smallest numbers in the list.
      </p>
      <p class="bold">Range: <span id="range"></span></p>
      <p>
        The <dfn>variance</dfn> of a list of numbers measures how far the values
        are from the mean, on average.
      </p>
      <p class="bold">Variance: <span id="variance"></span></p>
      <p>
        The <dfn>standard deviation</dfn> of a list of numbers is the square
        root of the variance.
      </p>
      <p class="bold">
        Standard Deviation: <span id="standardDeviation"></span>
      </p>
    </div>
  </body>
</html>
/* file: script.js */
const getMean = (array) => array.reduce((acc, el) => acc + el, 0) / array.length;


// User Editable Region

const getMedian = (array) => {
  const sorted = array.toSorted((a, b) => a - b);
  if (sorted.length % 2 === 0) {
    return getMean([sorted[sorted.length / 2], sorted[sorted.length / 2 - 1]]);
  }
  else {
   return sorted[Math.floor(sorted.length / 2)];
  }
}

// User Editable Region


const calculate = () => {
  const value = document.querySelector("#numbers").value;
  const array = value.split(/,\s*/g);
  const numbers = array.map(el => Number(el)).filter(el => !isNaN(el));
  
  const mean = getMean(numbers);

  document.querySelector("#mean").textContent = mean;
}
/* file: styles.css */
body {
  margin: 0;
  background-color: rgb(27, 27, 50);
  text-align: center;
  color: #fff;
}

button {
  cursor: pointer;
  background-color: rgb(59, 59, 79);
  border: 3px solid white;
  color: white;
}

input {
  background-color: rgb(10, 10, 35);
  color: white;
  border: 1px solid rgb(59, 59, 79);
}

.bold {
  font-weight: bold;
}

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/15.6.1 Safari/605.1.15

Challenge Information:

Learn Advanced Array Methods by Building a Statistics Calculator - Step 27

hello. i think it the array.toSorted() word. recheck how to sort an array

1 Like

Hi there!

Your code works from my end. Reset the challenge step and try again.

1 Like

Welcome to the forum @bukeliavishakha

Your code passes.
Reset the step and try again. If that doesn’t work, refresh the page, disable dark mode, disable ad blockers. Or, use another browser.
If the above steps do not work, you may need to restart the computer.

Happy coding

1 Like

Hi!
I changed .toSorted() back to .sort() and the code finally did pass! Thank you for your tip!
What’s interesting though - on the next step (step 28) the code was back to .toSorted()
I copied code from step 28 to step 27 and it doesn’t pass again.
It only passed with .sort()