# Learn Basic Algorithmic Thinking by Building a Number Sorter - Step 27

### Tell us what’s happening: it is daying decalre temp variable after nexted for loop , i did that but still it is giving me same problem again and again

const selectionSort = (array) => {
for (let i = 0; i < array.length; i++) {
let minIndex = i;

``````for (let j = i + 1; j < array.length; j++) {
console.log(array, array[j], array[minIndex]);
if (array[j] < array[minIndex]) {
minIndex = j;
}
}
let temp = array[i]
array[i] = array[minIndex]
array[minIndex] = temp
``````

}
}

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### Challenge Information:

Learn Basic Algorithmic Thinking by Building a Number Sorter - Step 27

It appears that you are trying to implement a selection sort algorithm. The error you’re encountering might be due to the placement of the `temp` variable declaration.

for (let i = 0; i < array.length - 1; i++) {
let minIndex = i;
for (let j = i + 1; j < array.length; j++) {
console.log(array, array[j], array[minIndex]);
if (array[j] < array[minIndex]) {
minIndex = j;
}
}
let temp = array[i];
array[i] = array[minIndex];
array[minIndex] = temp;
}

1. Moved the declaration of the `temp` variable inside the outer loop to ensure it’s declared after the nested loop.
2. Added initialization of `minIndex` variable inside the outer loop. This ensures that `minIndex` starts fresh for each iteration of the outer loop.

i hope With these corrections, your selection sort implementation should work as expected. If you’re still encountering issues, please provide more details or error messages for further assistance.

Best regard
Danish Hafeez | QA Assistant
ICTInnovations

1 Like

Declare the `temp` variable using the `const` keyword.
The rest of your code looks fine.

Happy coding

1 Like

thank you @teller890 , it worked

1 Like