Learn Basic JavaScript by Building a Role Playing Game - Step 140

JavaScript
1

Tell us what’s happening:

it need to transform the condition in ternary operator

### Your code so far

function attack() {
  text.innerText = "The " + monsters[fighting].name + " attacks.";
  text.innerText += " You attack it with your " + weapons[currentWeapon].name + ".";
  health -= monsters[fighting].level;
  monsterHealth -= weapons[currentWeapon].power + Math.floor(Math.random() * xp) + 1;
  healthText.innerText = health;
  monsterHealthText.innerText = monsterHealth;
  if (health <= 0) {
    lose();
  } else if (monsterHealth <= 0) {
    if (fighting === 2) {
      winGame();
    } else {
      defeatMonster();
    }
  }
}

health <= 0 ? lose() : (monsterHealth <= 0 ? (fighting === 2 ? winGame() : defeatMonster()) : null);

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Challenge Information:

Learn Basic JavaScript by Building a Role Playing Game - Step 140

2

Hey @MaryGothic
good work so far only turn the code below to use ternary operator not the whole if statement

Happy coding

3

and I made this

health <= 0 ? lose() : (monsterHealth <= 0 ? (fighting === 2 ? winGame() : defeatMonster()) : null);

but it doen’t work

4

Yap because you are using the tenary operator on the whole if statement you only need to convert the nested one ,The one with the “fighting ===2” as a condition

5

yes I know, it was for explain you the exercice: here my all solution and I don’ t know why return an error

function attack() {
  text.innerText = "The " + monsters[fighting].name + " attacks.";
  text.innerText += " You attack it with your " + weapons[currentWeapon].name + ".";
  health -= monsters[fighting].level;
  monsterHealth -= weapons[currentWeapon].power + Math.floor(Math.random() * xp) + 1;
  healthText.innerText = health;
  monsterHealthText.innerText = monsterHealth;
  
health <= 0 ? lose() : (monsterHealth <= 0 ? (fighting === 2 ? winGame() : defeatMonster()) : null);
}
6

Tenary operator only takes 3 arguments

condition ?  truthy:falsy

Right now in your code you are having tenary operator with multiple arguments which will not work

Dont change any other thing

7

Aaaaah I don’t understood the exercise, the ternary expression it was about the second condition! xD

8

Glad I could be of help Keep up the good work

9

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