Learn Interfaces by Building an Equation Solver - Step 24

Tell us what’s happening:

the biggest mind boggle ever can someone help i know why this is wrong because its on the wrong side that’s why, but how the hell do i get it to go like 2x+3=0

Your code so far

from abc import ABC, abstractmethod

class Equation(ABC):
    degree: int
  
    def __init__(self, *args):
        if (self.degree + 1) != len(args):
            raise TypeError(
                f"'Equation' object takes {self.degree + 1} positional arguments but {len(args)} were given"
            )
        if any(not isinstance(arg, (int, float)) for arg in args):
            raise TypeError("Coefficients must be of type 'int' or 'float'")
        if args[0] == 0:
            raise ValueError("Highest degree coefficient must be different from zero")
        self.coefficients = {(len(args) - n - 1): arg for n, arg in enumerate(args)}
        
    def __init_subclass__(cls):
        if not hasattr(cls, "degree"):
            raise AttributeError(
                f"Cannot create '{cls.__name__}' class: missing required attribute 'degree'"
            )

    def __str__(self):
        terms = []
        for n, coefficient in self.coefficients.items():
            if not coefficient:
                continue
            if n == 0:
                terms.append(f'{coefficient:+}')
            elif n == 1:
                terms.append(f'{coefficient:+}x')

# User Editable Region

        equation_string = ' =0'.join(terms)
        
        return equation_string

# User Editable Region

        
    
    @abstractmethod
    def solve(self):
        pass
        
    @abstractmethod
    def analyze(self):
        pass
        
class LinearEquation(Equation):
    degree = 1
    
    def solve(self):
        pass
    
    def analyze(self):
        pass
    
lin_eq = LinearEquation(2, 3)
print(lin_eq)

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Challenge Information:

Learn Interfaces by Building an Equation Solver - Step 24

and its because i haven’t concatenated it which is like “something” + " something else"

wait huh

equation_string = ' '.join(terms) + ' = 0'

ive done it but how the hell is it wrong

i think its cuz of
Also, to refine the output, remove any leading + sign from equation_string .
but idk how do it without

Use the ‘strip’ method on the equation_string, in the line that includes the ‘return’ statement.
Read about this method here:

equation_string = ' '.join(terms) + ' = 0'
        equation_string.strip('+')
        return equation_string

i’ve now got this, but it doesn’t work

never mind lol i was being dumb

Return equation_string.strip('+') literally. One line instead of two code lines:

        equation_string.strip('+')
        return equation_string
1 Like

yeah i know i done it, it was a dumb mistake

1 Like