Tell us what’s happening:
Here’s what the prompt is asking for:
“Within the QuadraticEquation class, define an init method. Use super() to call the init method from the parent class. Then, define a new attribute named delta, which stores the value of the discriminant of the equation.”
I’ve tried several ways to solve it, but I’m still getting errors. Can someone check if there’s something missing or something extra?
Your code so far
from abc import ABC, abstractmethod
class Equation(ABC):
degree: int
def __init__(self, *args):
if (self.degree + 1) != len(args):
raise TypeError(
f"'Equation' object takes {self.degree + 1} positional arguments but {len(args)} were given"
)
if any(not isinstance(arg, (int, float)) for arg in args):
raise TypeError("Coefficients must be of type 'int' or 'float'")
if args[0] == 0:
raise ValueError("Highest degree coefficient must be different from zero")
self.coefficients = {(len(args) - n - 1): arg for n, arg in enumerate(args)}
def __init_subclass__(cls):
if not hasattr(cls, "degree"):
raise AttributeError(
f"Cannot create '{cls.__name__}' class: missing required attribute 'degree'"
)
def __str__(self):
terms = []
for n, coefficient in self.coefficients.items():
if not coefficient:
continue
if n == 0:
terms.append(f'{coefficient:+}')
elif n == 1:
terms.append(f'{coefficient:+}x')
equation_string = ' '.join(terms) + ' = 0'
return equation_string.strip('+')
@abstractmethod
def solve(self):
pass
@abstractmethod
def analyze(self):
pass
class LinearEquation(Equation):
degree = 1
def solve(self):
a, b = self.coefficients.values()
x = -b / a
return x
def analyze(self):
slope, intercept = self.coefficients.values()
return {'slope': slope, 'intercept': intercept}
class QuadraticEquation(Equation):
degree = 2
# User Editable Region
def __init__(self, *args):
super().__init__(*args)
a, b, c = self.args
self.delta = b**2-4*a*c
# User Editable Region
def solve(self):
pass
def analyze(self):
pass
lin_eq = LinearEquation(2, 3)
print(lin_eq)
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Challenge Information:
Learn Interfaces by Building an Equation Solver - Step 30