Learn Introductory JavaScript by Building a Pyramid Generator - Step 103

Tell us what’s happening:

I’m I wrong is there a problem with the system here:

This is the task:
Declare a shifted variable, assign it the result of calling .shift() on your numbers array, and print the variable.

This is my answer:
const numbers = [1, 2, 3];
const shifted = numbers.shift();
console.log(shifted);

This is the error I’m getting:
// running tests
You should call .shift() on your numbers array.
// tests completed
// console output
1

Your code so far

const character = "#";
const count = 8;
const rows = [];

function padRow(rowNumber, rowCount) {
  return " ".repeat(rowCount - rowNumber) + character.repeat(2 * rowNumber - 1) + " ".repeat(rowCount - rowNumber);
}

// TODO: use a different type of loop
/*for (let i = 1; i <= count; i++) {
  rows.push(padRow(i, count));
}*/

/*while (rows.length < count) {
  rows.push(padRow(rows.length + 1, count));
}*/

/*for (let i = count; i > 0; i--) {
  rows.push(padRow(i, count));
}*/


// User Editable Region

const numbers = [1, 2, 3];

const shifted = numbers.shift();
console.log(shifted);


// User Editable Region


let result = ""

for (const row of rows) {
  result = result + "\n" + row;
}

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36

Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 103

where are the other lines that were there?

console.log(numbers);
const unshifted = numbers.unshift(5);
console.log(unshifted);

they were below the numbers array declaration. I don’t think they are the problem though. I have tried with them there and without but I keep getting the same error

I removed the lines after I got the error thinking they were the problem, but it didn’t solve anything

reset the step, add the requested code in the given empty lines

const numbers = [1, 2, 3];

const unshifted = numbers.unshift(5);
console.log(unshifted);
console.log(numbers);

const shifted = numbers.shift();
console.log(shifted);

I’m getting the same error, unless I’m writing the code wrong which I don’t think I am

you need to write in the two empty lines right below the numbers array

Okay now it works, thank you