Learn Recursion by Solving the Tower of Hanoi Puzzle - Step 24

Python
1

Tell us what’s happening:

According the requierement, the condition with elif should act when rods[source] is not empty. I guess it’s the part what I have done wrong in this part:

I’d wish someone help me to declarete properly a statement that mention the variable rods[source] would be considerate as not empty.

PD I was tring use !=

Your code so far

NUMBER_OF_DISKS = 3
number_of_moves = 2**NUMBER_OF_DISKS - 1
rods = {
    'A': list(range(NUMBER_OF_DISKS, 0, -1)),
    'B': [],
    'C': []
}

def move(n, source, auxiliary, target):
    # display starting configuration
    print(rods)
    for i in range(number_of_moves):
        remainder = (i + 1) % 3
        if remainder == 1:
            print(f'Move {i + 1} allowed between {source} and {target}')
            forward = False

# User Editable Region

            if not rods[target]:
                forward = True
            elif not rods[source] and rods[source][-1] < rods[target][-1]:
                print(rods[source])

# User Editable Region

        elif remainder == 2:
            print(f'Move {i + 1} allowed between {source} and {auxiliary}')
        elif remainder == 0:
            print(f'Move {i + 1} allowed between {auxiliary} and {target}')

# initiate call from source A to target C with auxiliary B
move(NUMBER_OF_DISKS, 'A', 'B', 'C')

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Challenge Information:

Learn Recursion by Solving the Tower of Hanoi Puzzle - Step 24

2
  • this part: elif not rods[source] and rods[source][-1] < rods[target][-1]:
    print(rods[source])
3

Welcome to the forum :wave:

rods[source] = 1
(not rods[source])

rods[source] = 0
(not rods[source])

Think if the expression in brackets will be true or false.

1 is equivalent to “not empty” and 0 is “empty”

Actually just test it out at the very beginning of your code:

x = 1
if not x:
    print((not x))

Experiment with setting x to 1 or 0