Learn Regular Expressions by Building a Password Generator - Step 59

Python
1

I have created the if statement, but I don’t know how to increment the count value by 1. I’ve tried count+ and count + 1 and count++ but none of them are correct. Can someone please help me out?

import re
import secrets
import string


def generate_password(length, nums, special_chars, uppercase, lowercase):
    # Define the possible characters for the password
    letters = string.ascii_letters
    digits = string.digits
    symbols = string.punctuation

    # Combine all characters
    all_characters = letters + digits + symbols

    while True:
        password = ''
        # Generate password
        for _ in range(length):
            password += secrets.choice(all_characters)
       
        constraints = [
            (nums, r'\d'),
            (lowercase, r'[a-z]'),
            (uppercase, r'[A-Z]'),            
            (special_chars, fr'[{symbols}]')            
        ]

# User Editable Region

        # Check constraints
        count = 0
        for constraint, pattern in constraints:
            if constraint <= len(re.findall(pattern, password)):
                count+

# User Editable Region

    return password

# new_password = generate_password(8)
# print(new_password)

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Learn Regular Expressions by Building a Password Generator - Step 59

2

Without being fancy, what’s the simplest way to add 1 to a variable?

3

it would be count + 1

4

Thank you for your time, I got it in the end and once I knew the answer it was very simple to understand.

1 Like
5

Using the += operator would work as well

1 Like
6

Ah okay. Thanks for the extra solution!

1 Like
7

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