Learn Regular Expressions by Building a Password Generator - Step 59

Python
1

Tell us what’s happening:

I understand what to do in this step but I don’t understand what the condition is checking. I’ve not come across for loops with more than one iterator (I think that’s what its called: the ‘constraint, pattern’ in my for loop). And I don’t understand what the .findall() method is checking against really? Can anyone help?

Your code so far

import re
import secrets
import string


def generate_password(length, nums, special_chars, uppercase, lowercase):
    # Define the possible characters for the password
    letters = string.ascii_letters
    digits = string.digits
    symbols = string.punctuation

    # Combine all characters
    all_characters = letters + digits + symbols

    while True:
        password = ''
        # Generate password
        for _ in range(length):
            password += secrets.choice(all_characters)
       
        constraints = [
            (nums, r'\d'),
            (lowercase, r'[a-z]'),
            (uppercase, r'[A-Z]'),            
            (special_chars, fr'[{symbols}]')            
        ]

# User Editable Region

        # Check constraints
        count = 0
        for constraint, pattern in constraints:
            if constraint <= len(re.findall(pattern, password)):
                

# User Editable Region

    return password

# new_password = generate_password(8)
# print(new_password)

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Challenge Information:

Learn Regular Expressions by Building a Password Generator - Step 59

2

Welcome to the forum @Wizzardish

Here is the error message from the console:
image

The if statement is not complete, so is raising an error.

You need to:

Inside the new conditional statement, increment the count value by 1 .

Happy coding