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Describe your issue in detail here.
how to do this code with one if statement with condition list comprehension
Your code so far
import re
import secrets
import string
def generate_password(length, nums, special_chars, uppercase, lowercase):
# Define the possible characters for the password
letters = string.ascii_letters
digits = string.digits
symbols = string.punctuation
# Combine all characters
all_characters = letters + digits + symbols
while True:
password = ''
# Generate password
for _ in range(length):
password += secrets.choice(all_characters)
constraints = [
(nums, r'\d'),
(lowercase, r'[a-z]'),
(uppercase, r'[A-Z]'),
(special_chars, fr'[{symbols}]')
]
# Check constraints
/* User Editable Region */
# list comprehension
count = 0
for constraint , pattern in constraints:
if constraint <= len(re.findall(pattern,password)):
count += 1
if count == 4:
break
/* User Editable Region */
break
return password
# new_password = generate_password(8)
# print(new_password)
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Challenge Information:
Learn Regular Expressions by Building a Password Generator - Step 61