Learn Special Methods by Building a Vector Space - Step 62 Step 61

Python
1

Tell us what’s happening:

I probably do not understand the requirement or i am missing something in my ne() method. Please have a look at the aforementioned method and provide a clue to what i am missing

Your code so far

class R2Vector:
    def __init__(self, *, x, y):
        self.x = x
        self.y = y

    def norm(self):
        return sum(val**2 for val in vars(self).values())**0.5

    def __str__(self):
        return str(tuple(getattr(self, i) for i in vars(self)))

    def __repr__(self):
        arg_list = [f'{key}={val}' for key, val in vars(self).items()]
        args = ', '.join(arg_list)
        return f'{self.__class__.__name__}({args})'

    def __add__(self, other):
        if type(self) != type(other):
            return NotImplemented
        kwargs = {i: getattr(self, i) + getattr(other, i) for i in vars(self)}
        return self.__class__(**kwargs)

    def __sub__(self, other):
        if type(self) != type(other):
            return NotImplemented
        kwargs = {i: getattr(self, i) - getattr(other, i) for i in vars(self)}
        return self.__class__(**kwargs)

    def __mul__(self, other):
        if type(other) in (int, float):
            kwargs = {i: getattr(self, i) * other for i in vars(self)}
            return self.__class__(**kwargs)        
        elif type(self) == type(other):
            args = [getattr(self, i) * getattr(other, i) for i in vars(self)]
            return sum(args)            
        return NotImplemented

# User Editable Region

    def __eq__(self, other):
        if type(self) != type(other):
            return NotImplemented
        return all(getattr(self, i) == getattr(other, i) for i in vars(self))

    def __ne__(self, other):
        if type(self) == type(other):
            return NotImplemented
        return not self.__eq__(other)

# User Editable Region

class R3Vector(R2Vector):
    def __init__(self, *, x, y, z):
        super().__init__(x=x, y=y)
        self.z = z

v1 = R2Vector(x=2, y=3)
v2 = R2Vector(x=0.5, y=1.25)
print(f'v1 = {v1}')
print(f'v2 = {v2}')
v3 = v1 + v2
print(f'v1 + v2 = {v3}')
v4 = v1 - v2
print(f'v1 - v2 = {v4}')
v5 = v1 * v2
print(f'v1 * v2 = {v5}')
print(v4 != v3)

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Challenge Information:

Learn Special Methods by Building a Vector Space - Step 61

2

I just figured that the if statement to verify if the two objects are of the same class is irrelevant since you are checking if attributes are not the same. Solved.

1 Like
3

if the type is the same, then you need to make it work, it’s when they are not the same that you return NotImplemented, like all the other methods

4

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