Learn String Manipulation by Building a Cipher - Step 38

Python
1

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Your code so far


/* User Editable Region */

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ':
        print(' ')

    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

/* User Editable Region */

```pls I am stuck on this if statement. Don't know where to implement the if statement so it can evaluate to true or false.
I tried using
if char == '  ':
       Print("' '")
esle:
    break
But none is working


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### Challenge Information:
Learn String Manipulation by Building a Cipher - Step 38
https://www.freecodecamp.org/learn/scientific-computing-with-python/learn-string-manipulation-by-building-a-cipher/step-38
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3

in the if block you are writing print(’ ')
insted of this you need to write print(‘space!’)

according to this instructions:
At the top of your for loop, replace print(char == ' ') with an if statement. The condition of this if statement should evaluate to True if char is an empty space and False otherwise. Inside the if body, print the string space! . Remember to indent this line.

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