Learn String Manipulation by Building a Cipher - Step 41

Python
1

Tell us what’s happening:

Describe your issue in detail here.

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char =='':
    print(false)
      
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:',char, 'encrypted_text:', encrypted_text)






# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 41

2

You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.

3

What error message are you getting? It can often help to look carefully at the exact wording of the error message.

4

Hi @kamau

Here are the instructions:

At the beginning of your loop body, print the result of comparing char with a space (' '). Use the equality operator == for that.

Here is your code:

There is no mention of using the if statement.
Just pass the argument mentioned in the instructions into the print call.
The string is supposed to enclose a space.

Happy coding

5

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