Learn String Manipulation by Building a Cipher - Step 41

Python
1

Tell us what’s happening:

Describe your issue in detail here.
I have entered the text where it is asking to compare char and then I enter the code char == ’ ’ and I keep getting and error what is wrong with this code I checked for spacing and all the code is entered correctly.

Your code so far

for char in text.lower():
print(‘Comparing results for char’, char == ‘’)
index = alphabet.find(char)
new_index = index + shift
encrypted_text += alphabet[new_index]
print(‘char:’, char, ‘encrypted text:’, encrypted_text)


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    print('Comparing results for char', char == '')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 41

2

You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.

3

I have edit and told what happen I also want to add that it is indented even, I see my copying the code here does not reflex the indent after for loop

4

Thank you for describing the issue as you see it.

Part of the requirement says:

At the beginning of your loop body, print the result of comparing char with a space (' '). Use the equality operator == for that.

I bet you that it is not intended for interpretation and that you literally JUST have to print what it says, instead of the little extra Comparing results for char

5

I deleted the text and added a space between the single quote and it ran successfully.

Thank you

6

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