Learn String Manipulation by Building a Cipher - Step 42

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Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ' = True
    elif = False 
    print('space!')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

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Hi, welcome to the forum!
We see you have posted some code but did you have a question?

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Welcome to the forum @Jason5

The if statement does not have the correct syntax.

Here is an article about the syntax of an if statement.

The elif is not required for this part of the code.

Happy coding

1 Like

Hello. I had the same issue. In order to help people who have the same problem, I have just copied and pasted my working codes (I mean this code pass the test) from the console to below. If it doesn’t work, care about the spaces between commas, print (‘space!’) must be indented, etc. I don’t know more yet.

–removed –

It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.

We are trying to cut back on the number of spoiler solutions found on the forum and instead focus on helping other campers with their questions and definitely not posting full working solutions.