Learn String Manipulation by Building a Cipher - Step 49

Python
1

Tell us what’s happening:

I’m getting indentation errors for line 4 but when don’t indent I get an error saying that I need to indent. I’ve reset the lesson twice and cleared my browser cache.

Your code so far


# User Editable Region

text = 'Hello Zaira'
shift = 3

    def caesar():

        alphabet = 'abcdefghijklmnopqrstuvwxyz'
        encrypted_text = ''

    for char in text.lower():
      if char == ' ':
        encrypted_text += char
    else:
        index = alphabet.find(char)
        new_index = (index + shift) % len(alphabet)
        encrypted_text += alphabet[new_index]
    print('plain text:', text)
    print('encrypted text:', encrypted_text)

# User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:129.0) Gecko/20100101 Firefox/129.0

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 49

2

Welcome to our community!

The declaration of the new function shouldn’t be indented.

3

Hey thanks for the response, when i dont indent the function line i get an error saying i need to indent everything under the shift = 3 line

4

Restart step.

alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ':
        encrypted_text += char
    else:
        index = alphabet.find(char)
        new_index = (index + shift) % len(alphabet)
        encrypted_text += alphabet[new_index]
print('plain text:', text)
print('encrypted text:', encrypted_text)

This is code given by default, before indented. Match every line before indentation with your indented code. You will see that some of the code lines are not indented properly.

  • ‘if’ starts under ‘char’,
  • ‘if’ and ‘else’ are aligned on the left etc.

P.S. Indent each code line four spaces.