Learn String Manipulation by Building a Cipher - Step 75

Python
1

Tell us what’s happening:

I have tried modifying the if statement, but it still does not pass . What should i do?

Your code so far

text = 'Hello Zaira!'
custom_key = 'python'

def vigenere(message, key, direction=1):
    key_index = 0
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    final_message = ''

    for char in message.lower():

/* User Editable Region */

        # Append space to the message
        if char.isalpha() == ' ':
            final_message += char

/* User Editable Region */

        else:        
            # Find the right key character to encode/decode
            key_char = key[key_index % len(key)]
            key_index += 1

            # Define the offset and the encrypted/decrypted letter
            offset = alphabet.index(key_char)
            index = alphabet.find(char)
            new_index = (index + offset*direction) % len(alphabet)
            final_message += alphabet[new_index]
    
    return final_message
    
encryption = vigenere(text, custom_key)
print(encryption)
decryption = vigenere(encryption, custom_key, -1)
print(decryption)

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 75

2

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3

Hello darlene,

So the .isalpha() method returns True if all characters are letters. So instead of having to check if a character is a space, we’re just going to check if the character is a letter in general. Hence you won’t need to check if it’s a space anymore.

1 Like
4

thank you
Have done the modification, it passes

2 Likes
5

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