Learn the Bisection Method by Finding the Square Root of a Number - Step 13

Python
1

Tell us what’s happening:

Not sure how to continue, I don’t thing there is enough information here to do the step?

Your code so far

def square_root_bisection(square_target, tolerance=1e-7, max_iterations=100):
    if square_target < 0:
        raise ValueError('Square root of negative number is not defined in real numbers')
    if square_target == 1:
        root = 1
        print(f'The square root of {square_target} is 1')
    elif square_target == 0:
        root = 0
        print(f'The square root of {square_target} is 0')

    else:
        low = 0
        high = max(1, square_target)
        root = None
        

# User Editable Region

        for _ in range(max_iterations):
            mid = (low + high) / 2
            square_mid = mid**2
           if tolerance in abs
            
            

# User Editable Region

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Challenge Information:

Learn the Bisection Method by Finding the Square Root of a Number - Step 13

2

Everything is here:

create an if statement to check if the absolute value of the difference between square_mid and square_target is within the specified tolerance.

create an if statement

If statement needs to have a colon at the end of the line

to check if the absolute value of

The abs() function returns the absolute value of a number,

abs() is a function, you can look up how it works
https://www.w3schools.com/python/ref_func_abs.asp

the difference between square_mid and square_target

Difference means you will need to use the - operator to find the difference between these two variables

is within the specified tolerance.

For example:

square_mid = 5
square_target = 10
tolerance = 2

square_mid - square_target = -5
abs(-5) = 5
(5 < tolerance) = False

Not within the tolerance in this case.

3

This is what I have now?

            mid = (low + high) / 2
            square_mid = mid**2
           if num <= 0:
              num = abs(square_mid - square_target) = tolerance```
4

I followed the suggestions by the help section it now reads the following and still not passing.

            mid = (low + high) / 2
            square_mid = mid**2
          if abs(square_mid - square_target) < tolerance:```
5

Looking good! :+1: Remember the body of an if can’t be empty, so you can use pass as a placeholder for now

6

still not working with pass

            mid = (low + high) / 2
            square_mid = mid**2
          if abs(square_mid - square_target) < tolerance:
           pass
7

Keep your indentation consistent. You can’t have it all over the place like JS :face_with_monocle: