Make a Person How I could reference the inside and outside argument?

JavaScript
#1

Tell us what’s happening:

The code is not working but I guess it’s because that the method setFullName doesn’t know which variable/argument to edit, I guess? How I fix this?

Your code so far


var Person = function(firstAndLast) {
  // Complete the method below and implement the others similarly
  var firstAndLast = firstAndLast.split(" ");
  this.getFullName = function() {
    return firstAndLast.join(" ");
  };
  this.getFirstName = function() {
    return firstAndLast[0];
  };
  this.getLastName = function() {
    return firstAndLast[1];
  };
  this.setFirstName = function(first) {
    firstAndLast[0] = first;
  }
  this.setLastName = function(last) {
    firstAndLast[1] = last;
  }
  this.setFullName = function(firstAndLast) {
   firstAndLast = firstAndLast;
  }
};

var bob = new Person('Bob Ross');
bob.setFullName("Haskell Curry");
bob.getFullName();

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/make-a-person

#2

It’s generally bad practice to name a variable in a function the same thing as a named argument.

#3

Call it something different: it’s up to you what the argument is called, it doesn’t have any special meaning.

#4

Not my mistake. The challenge says so.

#5

What are you talking about? The challenge doesn’t tell you what to name your variables.

#6

Fill in the object constructor with the following methods below:

getFirstName() getLastName() getFullName() setFirstName(first) setLastName(last) **_setFullName(firstAndLast)_**
#7

Then call the internal variable something different?

#8

I was trying to find a solution for this situation so in future, I would know what to do if I fallen in the same situation where I have to select a method with the argument name as the constructor main argument.

But after researching, it seems that it is pretty impossible. So yeah, I guess the only solution is to avoid this situation. Anyway, I solved it minutes ago. Thank you for help.

#9

Having the method argument named the same thing as the constructor’s argument isn’t a problem. It’s just a bad idea to name a variable the same thing as an argument.

#10