Multiple arguments while calling functions

Python
#1

I want to create a function that accepts multiple arguments (kwargs) while calling, but I want to ensure it gets at least one argument with a key, How should I do it?

#2

Is it supposed to be specific required keyword argument, or any keyword argument?

#3

Any key word argument

#4

Have you then tried checking if variable with keywords contains anything?

#5

I am working on the free code camp python project that involves probability:

First, create a Hat class in prob_calculator.py. The class should take a variable number of arguments that specify the number of balls of each color that are in the hat. For example, a class object could be created in any of these ways:

hat1 = Hat(yellow=3, blue=2, green=6)
hat2 = Hat(red=5, orange=4)
hat3 = Hat(red=5, orange=4, black=1, blue=0, pink=2, striped=9)
hat1 = Hat(yellow=3, blue=2, green=6)
hat2 = Hat(red=5, orange=4)
hat3 = Hat(red=5, orange=4, black=1, blue=0, pink=2, striped=9)

A hat will always be created with at least one ball.

I want to make sure the caller includes at least one keyword argument.

#6

In here, such check would be placed in the __init__ method of the class. How does it look like?

#7 
def __init__(self, **kwargs):
        self.kwargs = kwargs
        self.contents = []
        for k, v in self.kwargs.items():
            for i in range(v):
                self.contents.append(k)
#8

How could you check if kwargs variable contains anything?

#9

I would do it with the len( ) function:

if len(kwargs) > 0:
    do something
#10

And if it doesn’t satisfy this condition I would like the caller to enter inputs again. But I am also wondering if there is a way in which the instance itself is not to be created (python returns error) unless we pass some keyword argument.

#11

You could raise some exception when kwargs is empty. That will stop execution with an error.

#12

How could I do that?

#13

Using the raise keyword, ie.:

raise NameOfTheException
#14

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