# Need a clarification regarding Destructuring

Tell us what’s happening:
Could anyone explain to me how are we accessing max, min :
// const half = ({max, min}) => (max + min) / 2.0; //

without specifying that it’s located in the const stats?
What if we had more constants with min, max, average, etc. values?

``````
const stats = {
max: 56.78,
standard_deviation: 4.34,
median: 34.54,
mode: 23.87,
min: -0.75,
average: 35.85
};

// Only change code below this line
const half = ({max, min}) => (max + min) / 2.0;
// Only change code above this line

``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:83.0) Gecko/20100101 Firefox/83.0`.

Challenge: Use Destructuring Assignment to Pass an Object as a Function’s Parameters

the function works with any finction that has a `max` and `min` property

for the `stats` object in particular, just call the function with it as an argument `half(stats)`

But since it is outside of a function, how does it understand that we are referring to that particular min/max? What if I create 2 similar const objects and then call the given formula? I tried doing that by copying the const stats, changing the name and values of min/max and calling the code and I’m passing the challenge.

For example :

``````const stats = {

max: 56.78,

standard_deviation: 4.34,

median: 34.54,

mode: 23.87,

min: -0.75,

average: 35.85

};

const statsa = {

max: 52.78,

standard_deviation: 4.34,

median: 34.54,

mode: 23.87,

min: -0.25,

average: 35.85

};

const statssss = {

max: 54,

standard_deviation: 4.34,

median: 34.54,

mode: 23.87,

min: -1,

average: 35.85

};

// Only change code below this line

const half = ({max, min}) => (max + min) / 2.0;

// Only change code above this line
``````

nothing happens until you call the function

when you are the function with an argument you are telling the function which object to use

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1 Like

It makes perfect sense now. Thanks and thank you for the formatting tip!