Need help with Return Early Pattern for Functions

JavaScript
1

Tell us what’s happening:
i made a if statemnt wit an && so it can evaluate both a less than b and b less than a.
but i dont understand how to make the program return undefined. i tried to move the curly braces to the bottom so that the math return goes in the statement but i don’t get the undefined.

Your code so far


// Setup
function abTest(a, b) {
  // Only change code below this line
  if(a < b && b < a){
  
  }
  // Only change code above this line

  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
 }

// Change values below to test your code
abTest(2,2);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:63.0) Gecko/20100101 Firefox/63.0.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

You can either just return; or you can return undefined;

3

Modify the function abTest so that if a or b are less than 0 the function will immediately exit with a value of undefined .

(a < b && b < a) will always return false fyi.

1 Like
4

i don’t undestand should i use (a==0 && b==0)

5

What are you trying to check for?

(a==0 && b==0) will be true if a is equal to 0 and b is also equal to 0.

6

@zayno70 I just finished this challenge. Double check your logical operator against the parameters of the challenge. The challenge asks to check if either a or b is < 0 return undefined. Your if statement is checking if both a < b and b < a to return something.

9

thanks for the help i found the answer with searching google, i had to use the a<0 || b<0, and it worked!!! :smile: