# Need help with Return Early Pattern for Functions

Tell us what’s happening:
i made a if statemnt wit an && so it can evaluate both a less than b and b less than a.
but i dont understand how to make the program return undefined. i tried to move the curly braces to the bottom so that the math return goes in the statement but i don’t get the undefined.

``````
// Setup
function abTest(a, b) {
// Only change code below this line
if(a < b && b < a){

}
// Only change code above this line

return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}

// Change values below to test your code
abTest(2,2);
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:63.0) Gecko/20100101 Firefox/63.0`.

You can either just `return;` or you can `return undefined;`

Modify the function `abTest` so that if `a` or `b` are less than `0` the function will immediately exit with a value of `undefined` .

`(a < b && b < a)` will always return false fyi.

1 Like

i don’t undestand should i use (a==0 && b==0)

What are you trying to check for?

`(a==0 && b==0)` will be true if `a` is equal to `0` and `b` is also equal to `0`.

@zayno70 I just finished this challenge. Double check your logical operator against the parameters of the challenge. The challenge asks to check if either a or b is < 0 return undefined. Your if statement is checking if both a < b and b < a to return something.

thanks for the help i found the answer with searching google, i had to use the a<0 || b<0, and it worked!!!