I have a new solution using recursion.
function sumAll(arr) {
const [a,b] = arr;
if (a === b)
return a;
else if(a > b)
return a + sumAll([a-1, b])
else
return a + sumAll([a+1, b])
}
sumAll([1, 4]);
I have a new solution using recursion.
function sumAll(arr) {
const [a,b] = arr;
if (a === b)
return a;
else if(a > b)
return a + sumAll([a-1, b])
else
return a + sumAll([a+1, b])
}
sumAll([1, 4]);