Object Oriented Programming - Use Inheritance So You Don't Repeat Yourself

[Saidur_Shemanto]

Tell us what’s happening:

My question is, in both Cat.prototype and Dog.prototype, if I change the constructor to Animal instead of Cat and Dog, It still works
Help me to clear my concept

Your code so far

function Cat(name) {
  this.name = name;
}

Cat.prototype = {
  constructor: Cat,
  eat: function() {
    console.log("nom nom nom");
  }
};

function Bear(name) {
  this.name = name;
}

Bear.prototype = {
  constructor: Bear,
  eat: function() {
    console.log("nom nom nom");
  }
};

function Animal() { }

Animal.prototype = {
  constructor: Animal,
  eat: function() {
    console.log("nom nom nom");
  }

};
Cat.prototype = {
  constructor: Animal
};

Bear.prototype = {
  constructor: Animal
};

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Challenge Information:

Object Oriented Programming - Use Inheritance So You Don’t Repeat Yourself

freeCodeCamp.org

[lasjorg]

You are reassigning the prototype so they do not have the eat method as an instance method and it is only testing if eat is a property on Cat and Bear.

function Cat(name) {
  this.name = name;
}

Cat.prototype = {
  constructor: Cat,
  eat: function() {
    console.log("nom nom nom");
  }
};

console.log(Cat.prototype.hasOwnProperty('eat')) // true

Cat.prototype = {
  constructor: Cat,
};

console.log(Cat.prototype.hasOwnProperty('eat')) // false