Palindrome Checker answer

[n1c3cleantoilet]

I have figured out the solution to this problem but I was wondering if I can make it more efficient.

How could I change the regex in split so that I do not need to add the filter?

Thanks in advance

function palindrome(str) {
str = str.toLowerCase().split(/(?=\w)|\W/)
str = str.filter(element => {
  if (element === '-' || element === '' || element === '_') {
    return false
  }
  return true
})
console.log(str)

for (let i=0; i<str.length; i++) {
  if (str[i] !== str[str.length-1-i]) {
    return false
  }
}
return true;
}



palindrome("_eye");

  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/94.0.4606.81 Safari/537.36

Challenge: Palindrome Checker

Link to the challenge:

freeCodeCamp.org

[bbsmooth]

@n1c3cleantoilet

How could I change the regex in split so that I do not need to add the filter?

I would concentrate on the note in the instructions:

“Note: You’ll need to remove all non-alphanumeric characters”

Reword that as “remove anything BUT alphanumeric characters.” You might consider doing this first before splitting.