Printing the second lowest in an Object array

[Paulola]

function secondCheapest(bookObj){
  const price = bookObj.map(bookObj => {
    return bookObj.price
    })
 const name = bookObj.map(bookObj => {
   return bookObj.title
 })
 
  let lowest = Math.min(...price)
  let second = price.filter(value => value != lowest)
  let n = Math.min(...second)
return n
}
console.log(secondCheapest([
    {title:'Fox In Socks', price:32.20},
    {title:'The Cat In The Hat', price:16.20},
    {title:'Green Eggs and Ham', price:28.50},
    {title:'Thinking Fast and Slow', price:58.80},
    {title:'War and Peace', price: 5.20}
]));

I
I’m stuck here please help… I’m trying to return the second lowest price of the book here, but my code is printing the second price only. How can I make the code to print both the title and the price such as… title:‘The Cat In The Hat’, price:16.20

[prasadsaya]

@Paulola

let n = Math.min(...second)

The variable n has the second lowest price. It is possible to filter the input array bookObj based upon the condition on the price property value matching the value of n.

[Paulola]

I got the correct output, just that the price doesn’t include the title

[admit8490]

Do you need to return this?

{ title: 'The Cat In The Hat', price: 16.2 }

Just filter the array as said above. Your n === 16.2, so it’s correct, but it’s just the number.

For your solution, you dont need this:

@Paulola

const name = bookObj.map(bookObj => {
   return bookObj.title
 })

[Paulola]

Yes. I want to print the title and the book price. My code is only printing the price