Question about "Basic Algorithim Scripting: Mutations"

JavaScript
1

SPOILER ALERT FOR THOSE THAT HAVE NOT DONE THIS CHALLENGE YET!!!

This question is about the Basic Algorithim Scripting:Mutations challenge.

Can someone explain to me why we are checking to see if(target.indexOf(test)[i] === -1)… ?
Why are we looking for a -1?

The basic solution to this is: 
function mutation(arr) {
  var test = arr[1].toLowerCase();
  var target = arr[0].toLowerCase();
  for (i=0;i<test.length;i++) {
    if (target.indexOf(test[i]) === -1)
      return false;
  }
  return true;
 }
2

I’ve edited your post for readability. When you enter a code block into the forum, remember to precede it with a line of three backticks and follow it with a line of three backticks to make easier to read. See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (</>) will also add backticks around text.

markdown_Forums

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3

The answer to your question is that indexOf() returns -1 when the item is not found.

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4

@ArielLeslie you are the best meat popsicle here!

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