Question on functionality of alternative solution for Iterate Through All an Array's Items Using For Loops Iterate through all of an array's

[bananahair]

Tell us what’s happening:
Describe your issue in detail here.
The solution for this is finding any instance of elem and returning an array without elem and it uses indexOf to parse out non-elem to push into newArr.
I used a 2-D loop to do this (see below). The program doesn’t accept this and I’m wondering if there’s something wrong with using a 2d loop to suss out not-elem as opposed to using indexOf . What is wrong with the method I used?

  **Your code so far**

function filteredArray(arr, elem) {
  let newArr = [];
  // Only change code below this line
for(let i = 0; i < arr.length; i++){
  for(let j = 1; j < arr[i].length; j++){
    if(arr[i][j] !== elem){
      newArr.push(arr[i][j]);
    }
  } console.log(newArr)
}
  // Only change code above this line
  return newArr;
}

console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));

  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/96.0.4664.93 Safari/537.36

Challenge: Iterate Through All an Array’s Items Using For Loops

Link to the challenge:

freeCodeCamp.org

[sanity]

Using indexOf might be more convenient depending who you ask, but no, using nested loop here doesn’t make it wrong.

Take a closer look at the test inputs and outputs, function is expected to do something slightly different than it is doing now.

[bananahair]

If the issue that the problem asks me to remove arrays containing elem, but my nested loops only remove individual elem rather than the entire array containing them?

[sanity]

Yes, that sounds about right.