Recursion problem 1

JavaScript
1

Tell us what’s happening:
Hello,
although my code return exactly what is required, the computer doesnt accept it.
could u please help me why?
regards,

Your code so far


var a=[];
function rangeOfNumbers(startNum, endNum) {
if(startNum==endNum)
{
  a.push(startNum)
  return a;
}
else{
  a.push(startNum);
  rangeOfNumbers(startNum+1,endNum)
  
  return a;
}
};

console.log(rangeOfNumbers(6,9));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.149 Safari/537.36.

Challenge: Use Recursion to Create a Range of Numbers

Link to the challenge:

2

It worked perfectly in my computer.

4

Your code contains global variables that are changed each time the function is run. This means that after each test completes, subsequent tests start with the previous value. To fix this, make sure your function doesn’t change any global variables, and declare/assign variables within the function if they need to be changed.

Example:

var myGlobal = [1];
function returnGlobal(arg) {
  myGlobal.push(arg);
  return myGlobal;
} // unreliable - array gets longer each time the function is run

function returnLocal(arg) {
  var myLocal = [1];
  myLocal.push(arg);
  return myLocal;
} // reliable - always returns an array of length 2