Remove Items Using splice() help

need help with this code

Your code so far


function sumOfTen(arr) {
  // change code below this line
 let a = arr.splice(1,1);
 let b = arr.splice(3,1);
  // change code above this line
  return arr.reduce((a, b) => a + b);
}

// do not change code below this line
console.log(sumOfTen([2, 5, 1, 5, 2, 1]));

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-data-structures/remove-items-using-splice

So the challenge is to remove enough numbers from the given array so that the final list sums up to 10.
Here’s the original list:
[2, 5, 1, 5, 2, 1]

And then here’s what happens when your code runs
let a = arr.splice(1,1); //remove one item from position index 1

a is
[5]
arr is now
[2,1,5,2,1]

let b = arr.splice(3,1); //remove one item from position index 3
b is
[2]
arr is also
[2,1,5,1]

return arr.reduce((a, b) => a + b);
This produces the sum of 2+1+5+1 = 9

Therefore the challenge is not met.

ohh i thought i have to splice numbers from the array and assign those to a &b

oh oops, you’re right. The a and b above are the deleted items. I’ll edit that…

but to be clear, the ‘a’ and ‘b’ in the scope of the ‘reduce’ are completely different things than the ‘a’ and ‘b’ arrays you made…

Following your logic, you could just splice from the 2nd item and then 2 items.

let a = arr.splice(1,2);

a would already add up to 10. You bet that you could just add up 0 by defining b as so…

can i used return value of arr.splice as parameter in function

function sumOfTen(arr) {

// change code below this line

let a = arr.splice(1,1);

let b = arr.splice(1,1);

// change code above this line

return arr.reduce((a, b) => a + b);

}

// do not change code below this line

console.log(sumOfTen([2, 5, 1, 5, 2, 1]));