Removing time stamp and jump to a new line

Python
1

I have a text like this :
[14:38] kkkk[15:06] check [15:07] gffgfgfgfgfgfgfgfgfgfgfgf [15:08] dasdsadsadsdsds [15:09] tessssttt
I want to replace the time in the brackets with - and that each line starting with the time stamp will be separated and will be moved to a new line.
So the final output will be something like this :

  • kkkk
  • checkddssfsf
  • gffgfgfgfgfgfgfgfgfgfgfgf
  • dasdsadsadsdsds
  • tessssttt ssaf dsfdsf scfc
    For replacing the time stamp i have this line ‘mod_string = re.sub(r’([^)]*)’ ,’’,orig_string)’
    How should i proceed and which action should be committed first?
2

share your current python code

3

What is your problem? You got two clear goals, you can use regular expressions.

4

Maybe it will be more clear now , i have this code :

import re
orig_string = "[14:38] kkkk[15:06] checkccc [15:07] "
mod_string = re.sub(r'\([^)]*\)','',orig_string)
print(mod_string)

Now if i run it, the time will be removed but i will have a big string in one line : " kkkk checkccc "
I actually wanted to separate each string line by line but instead of something like this :
[14:38] kkkk
[15:06] check
[15:07] gffgfgfgfgfgfgfgfgfgfgfgf
[15:08] dasdsadsadsdsds
[15:09] tessssttt
it should look like this :

  • kkkk
  • check
  • gffgfgfgfgfgfgfgfgfgfgfgf
  • dasdsadsadsdsds
  • tessssttt
5

try this

orig_string = “[14:38] kkkk[15:06]”
mod_string = orig_string. translate ({ord(c): " " for c in “!@#$%^&*(){};:,./<>?|`~-=_+”})
print(mode_string)

6

re.sub() replaces the pattern of the first argument with the string in the second - ofcourse if you tell it to replace it with an empty string, you will just delete it.

However according to your task, you want to replace it with [-], so why don’t you do that?
Then do you want to save the result as a string and add newlines, or as an array and split the string?

7

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