Tell us what’s happening:
Hello, I trying to fix this lesson and understand exactly what are going in the code.
I did until here, my doubts is about the “else return”. For what I understood, I need return the sum with the first arr[index].

**Your code so far**

function sum(arr, n) {
// Only change code below this line
if ( n <= 0) {
return 1;
} else {
return sum += arr[0];
}
// Only change code above this line
}

**Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.99 Safari/537.36

You need the first n numbers of the array added together. So if n was 5, and the array was [1,2,3,4,5,6,7,8,9,10], we would want 1+2+3+4+5. If n was 3, we would want the first 3 numbers added together, not just the first number in arr.

The other thing is you need to call the sum function recursively. So your else return needs sum(arr, n), not just sum. And n eventually has to reach 0 . The second example in the test is closer to what you need, but you will need to change things around for it to work.

Thanks for your help. I did the modifications that I think and I got to this code, i know its wrong but i understand about calling sum recursively. My question now is the second parameter to do the sum.

function sum(arr, n) {
// Only change code below this line
if ( n <= 0) {
return 1;
} else {
return sum(arr, n) += (n[0] + n);
}
// Only change code above this line
}

Remember that our base case is n <= 0. When you keep calling sum with the same value of n, will n ever equal zero?
And we eventually want to add all the n numbers in the array together, is n[0] our array numbers?