Rest Operator not working

JavaScript
#1

Tell us what’s happening:

Wrote this, but the function is not passing. Can’t figure what’s wrong…

Thnks
Your code so far

const sum = (function() {
  "use strict";
  return function sum(...arr) {
    const args = [ ...arr ];
    return args.reduce((a, b) => a + b, 0);
  };
})();
console.log(sum(1, 2, 3));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/76.0.3809.100 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-the-rest-operator-with-function-parameters/

#2

Just don’t spread the arr twice.

const sum = (function() {
  "use strict";
  return function sum(...args) {
    return args.reduce((a, b) => a + b, 0);
  };
})();
console.log(sum(1, 2, 3));
#3

That worked,

However my solution is working also on a editor… This means that the code is more strict on FCC.
Quite confusing, I understand that const args = [ ...arr ]; is redundant but it should still run…

#4