Return Early Pattern for Functions code problem

JavaScript
1

I see another solution for this challenge with if and it works, but i think that i can use case.

Where is the problem in my code?

Your code so far


// Setup
function abTest(a, b) {
  // Only change code below this line

  switch (abTest){
  case a < 0:
  return undefined;
  break
  case b < 0:
  return undefined; 
  break;
  }
  
  
  // Only change code above this line

  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}

// Change values below to test your code
abTest(2,2);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.2; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

It’s the way you are trying to use the switch statement
This translate to

if (abTest === (a < 0)) {
   return undefined;
} else if (abTest === (b < 0)) {
   return undefined;
}

For starting you don’t have a variable abTest defined in your code

You may want to change approach here

Also, check the documentation on switch: