# Return Largest Numbers in Arrays - logic help

Tell us what’s happening:

So I cannot pass this test. The logic seems correct but I keep failing a single test:

largestOfFour([[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]]) should return [25, 48, 21, -3].

Not only that, but the only thing that is not passing of that test is the last index of the result array. It keeps returning “0”. I can set the re-assignment of the `largestNumber` in the first for loop to -100 and it works, but that becomes static and won’t pass if there are lesser -numbers in the array.

Can somebody point me in the right direction? am I missing something? is my logic off?

``````
function largestOfFour(arr) {
let largestNum = 0;
let result = [];

for (let i = 0; i < arr.length; i++){

largestNum = 0;

for (let j = 0; j < arr[i].length; j++){

if ( arr[i][j] > largestNum ){

largestNum = arr[i][j];

}

}

result.push(largestNum);

}

return result;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/76.0.3809.100 Safari/537.36`.

You don’t have to set `largestNum` to a hard-coded value. I suggest just setting it to the first value in the sub-array.

Thank you Ariel. Much appreciated.