# Return Largest Numbers in Arrays ! solution please?

Return Largest Numbers in Arrays ! solution please?
0.0 0

#1

Tell us what’s happening:

This code is not working, why???

Your code so far

``````function largestOfFour(arr)
{
var arr2=[];

// You can do this!
for(var i=0;i<arr.length;i++)
{

arr[i].sort();

for(var j=0;j<arr[i].length;j++)
{
if(j===arr[i].length-1)
{
arr2.push(arr[i][j]);
}

}
}

return arr2;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
``````

Your Browser User Agent is: `Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:59.0) Gecko/20100101 Firefox/59.0`.

Link to the challenge:

#2

Why .sort() function not working in the last sub-array?

#3

you need a compare function 4 ur .sort() mdn docs;
when compared as strings 857 is larger than anything starting with 1

#4

think youll need to use sort like this

``````var numbers = [1000,1001,857,1];
numbers.sort(function(a, b) {
return a - b;
});
``````

you can read about it here https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort

Better way to do things would be using Math.max()