Returning a statement w/o using a variable

JavaScript
1

Hello! Can someone help me understand wwhy this loop is returning “undefined”. also, oonce arr has been looped through w/o any instance of “October”, I’d like to return “Have a great day”

function holidays(arr) {
  // Do not use a variable to store your result 
  // ADD CODE HERE
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] != "October") {
      i++
    } else if (arr[i] === "October") {
      return "Happy Halloween"
    } 
  }
}

// Uncomment these to check your work!
const months = ["April", "May", "June", "October"];
const animals = ["Cats", "Dogs", "Pigs"];
console.log(holidays(months)); // should return: "Happy Halloween"
console.log(holidays(animals)); // should return: "Have a great day!"
2

The for loop is only returning “Happy Halloween” if arr[i] === "October". If that doesn’t happen then the function just ends. And do you know what value gets returned automatically if a function doesn’t explicitly return a value?

3

shouldnt it at least return “Happy Halloweem” for the first array?

here is the update

function holidays(arr) {
  // Do not use a variable to store your result 
  // ADD CODE HERE
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] != "October") {
      i++
    } else if (arr[i] === "October") {
      return "Happy Halloween"
    } 
    else {return "Have a great day!"}
  }
}

// Uncomment these to check your work!
const months = ["April", "May", "June", "October"];
const animals = ["Cats", "Dogs", "Pigs"];
console.log(holidays(months)); // should return: "Happy Halloween"
console.log(holidays(animals)); // should return: "Have a great day!"
4

So you are doing some extra incrementing that you don’t need. In your first if statement you are incrementing i if the value doesn’t equal “October”. But you have to remember that the for loop is also incrementing i every time through the loop. So when the value doesn’t equal “October” then you are incrementing i twice. Do you see how that will cause you to skip some strings in the array?

5

I pointed it out in the other topic, if you increase i inside the loop too you are jumping over some array elements, not checking them

6

hmm the only reason i was using i++ is because im not sure how else to not do anything if a certain condition is met. thans so much for yalls help

7

have no code execute

like

for (let i = 0; i < arr.length; i++) {
   // no code execute for all values o f i
}

having i++ is the worst choice as that means that aome indexes are never checked

8