Reverse a string & Find the Longest Word in a String

Question 1: I am wondering why in the first solution, shown here:

function reverseString(str) {
  for (var reversedStr = "", i = str.length - 1; i >= 0; i--) {
    reversedStr += str[i];
  return reversedStr;

Why the str.length has a -1 after it? Doesn’t the -1 leave out the last letter, for example if the string is “hello” won’t it miss out “o”? Sorry if this is a really dumb question.

Question 2:

function findLongestWordLength(str) {
  var words = str.split(' ');
  var maxLength = 0;

  for (var i = 0; i < words.length; i++) {
    if (words[i].length > maxLength) {
      maxLength = words[i].length;

  return maxLength;

In the code explanation it says: Then check for the longest word by comparing the current word to the previous one and storing the new longest word - referring to the if statement. But I don’t understand how it is comparing with the one before it - if maxLength is 0 then how are we sure that something just because it is bigger than 0 that it is the longest word?

It is to do with how an array (a string is basically just an array of characters) is indexed from 0 rather than 1. So counting becomes:
0,1,2,3,4,5,6,7,8,9 (there are 10 elements here), rather than 1,2,3,4,5,6,7,8,9,10 (as we would usually count to ten… note there are also 10 elements here).

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thanks. Although I just saw this lesson:

and it seems like it’s more to do with the fact that we need to specify which character we mean, and -1 is the most logical way to specify it as it kind of means the first from the end, if you see what I mean? I feel like this makes more sense than the indexing reason that you suggested? What do you think

@chunzg It is 100% related to how strings (and arrays) are indexed.

Let’s say I have a string with 4 characters:

var myStr = ['abcd'];

If I want to reference the last character 'd', then I would write:

console.log(myStr[myStr.length - 1]); // displays 'd'

The length of the string is 4, but the last character resides at index 3, which is why the myStr.length - 1 is used.

In the challenge, you need to start iterating from the last character in thestring, which is why the variable i must start at str.length - 1.

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In this case they are decrementing the length of the string by a variable i. Which results in running a for loop from str[str.length-1] down to str[0]. So if the string is “Happy”, str.length = 5 (because there are five characters). So the loop does the following (note ‘i’ initially equals str.length-1, and in each iteration it is decremented by 1):
reversedStr = “”
reversedStr = reversedStr + str[str.length -1] = “” + str[5-1] = “Y”
reversedStr = reversedStr + str[str.length-1-1] = “Y” + str[(5-1)-1] = “YP”
reversedStr = reversedStr + str[str.length-1-2] = “YP” + str[((5-1)-1)-1] = “YPP” …
So they are still using the index, it is just that they are starting from one less than the length of the string (i.e. 4 in the string “Happy”) and then decrementing that index by one on each iteration, until they reach the zeroth element str[0] = ‘H’ after which the loop exits as it has reached the termination condition (as 0 - 1 = -1).

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Oh I see! Thank you so much.
It’s super confusing because sometimes I don’t know when the number is referring to an index or to an actual number! :sweat:

i is an actual number. It just so happens it represents the index of the string.

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:roll_eyes: ok. I’ll get there!

as a stopped and beginner person on JS applications, for this task I come up with this solution, I think it is easy to understand for a beginner like me lol

function findLongestWordLength(str) {
  var str2 = str.split(' ');
  var arr = [];
  for(var i= 0;i< str2.length; i++){
  const result = Math.max.apply(null, arr);
  return result;

findLongestWordLength("The quick brown fox jumped over the lazy dog");

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