# Review Algorithmic Thinking by Building a Dice Game - Step 7

### Tell us what’s happening:

Does anybody know what did I do wrong because when I run the code, it gives me this instructions: When the array has less than three of the same number, your getHighestDuplicates function should update the final radio option with , score = 0.

``````<!-- file: index.html -->

``````
``````/* file: script.js */
// User Editable Region

const getHighestDuplicates = (arr) => {
const counts = {}

for(const num of arr) {
if(counts[num]) {
counts[num] + 1
}else {
counts[num] = 1
}
}

let highestCount = 0;
for(const num of arr) {
const count = counts[num];
if(count >= 3 && count > highestCount) {
highestCount = count
}
if(count >= 4 && count > highestCount)
highestCount = count
}
diceValueArr.reduce((a,b) => a+b, 0);
const sumOfAllDice = diceValueArr;

if(highestCount >= 4) {
}
if(highestCount >= 3) {
}

};

// User Editable Region
``````
``````/* file: styles.css */

``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/127.0.0.0 Safari/537.36`

### Challenge Information:

Review Algorithmic Thinking by Building a Dice Game - Step 7

When does this line of code run?

Answer: every time getHighestDuplicates is called. Is that correct?

Hmmmmmm

this line code is referring to the final radio option, with the index 5, and a score of 0

Yes so, should it be updated all the time?

yes if the ‘three-of-a-kind’ has less than three of occurrences

“If”, kind of like an `if` statement?

Look at your previous `updateRadioOption` calls. The new one is missing something.