Seek and destroy , Diff Two Arrays

Tell us what’s happening:

Your code so far

function destroyer(arr) {

let qwe = Array.from(arguments).slice(1);

return arr.concat(qwe).filter(wer =>  !qwe.includes(wer));


destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Why concat() doesn't work? if they are two different arrays ([1,2,3,1,2,3],[2,3]) now.
How filter() works here if both of the array are not concatenated()?

But the same thing works here for the below code

function diffArray(arr1, arr2) {
  return arr1
    .filter(item => !arr1.includes(item) || !arr2.includes(item));

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]);

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User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/78.0.3904.108 Safari/537.36.

Challenge: Seek and Destroy

Link to the challenge:

Your code isn’t the same though? Concat works fine, you just aren’t doing what the other example you posted is doing

Thanks for the help.

The first code I mentioned works with or without concat() but
the second code doesn’t work without concat ().

Can you figure it out ?

the first one is removing specific values from the first array, the second one is providing a difference of the first and second one where it returns only values not present in the first array

Thank you very much for your consideration.