Seek and Destroy help needed

JavaScript
#1

So I’m confused as to why the for loop is not continuing through. It removes the first item from the newly created x array, but not the subsequent items. Is this just a syntax thing or what? My result is (1,3,1,3).

function destroyer(arr) {
  var x = Array.from(arguments);
  x.shift();
  
  var result = arr.filter(function(val){
    for (var i =0; i <=x.length; i++){
      return val !== x[(i)];
    }
  });
  
  // Remove all the values
return result;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

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Link to the challenge:
https://www.freecodecamp.org/challenges/seek-and-destroy

#2

The return statement below only allows the for loop to iterate one time.

return val !== x[(i)];

Once the return statement is encountered, the for loop exits and the filter function moves to the next element in arr.

#3

Good to know, I’ve only, as of yet, encountered filter prototypes with a return. Is there a better statement to use that would still allow the loop to continue?

#4

Instead of a for loop, why not check if val is an element in x? You could use the indexOf or the includes function. Just make sure you are returning a Boolean expression when using the functions.

#5