Tell us what’s happening:
I’ve been slowly working through these problems and seen a particular piece of code several times. I kind of know what it does but was hoping someone might be able to explain it a little better
function swap(a, b, arr){
let tmp = arr[a];
arr[a] = arr[b];
arr[b] = tmp;
}
Cheers!
Sure. It’s a little deceptive, though. Almost more an object thing than an array. But here’s the logic:
- Given two index numbers and an array, this is a mechanism to exchange them.
- First, store the element at the first index to a variable. This way we don’t lose it.
- Next, move the array element at the second index into that first index position.
- Last, that value we stuck in a variable? It replaces the old value at that second index.
Interestingly, if you call it with two property names and an object, like so:
. swap(“firstName”, “lastName”, studentRecordObject):
… It would still work.
1 Like
Cool, that explains a lot. Thanks!