Simplified a little

1

Continuing the discussion from freeCodeCamp Algorithm Challenge Guide: Return largest Numbers in Arrays:

I simplified it a little
function largestOfFour(arr) {
// You can do this!
var max=;
for (var i= 0; i<arr.length;i++)
{
max[i]=arr[i][0];

for(var j= 0; j<arr[i].length;j++){

   if(arr[i][j]>max[i]){
      max[i]=arr[i][j];
    }//if
  
  } //for
}//for

return max;

} //function

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2

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4

Ok, I am sorry, I am new to the fcc community.

5

i know this is old one but i am just learning here, i tried this code and it did work.
i dont think i am that genius so here it is:

function largestOfFour(arr) {

  return arr.map(x =>{

    return Math.max(...x)

  });

}
5 Likes
6

//Used the inbuilt Math.max function with the spread operator for a simple solution
function largestOfFour(arr) {

var a=[ ]
for(let i=0;i<arr.length;i++)
{
var max=Math.max(…arr[i])
a.push(max)
}
return a
}
largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

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