a hint would be good
Your code so far
function smallestCommons(arr) {
let newArr = [];
for (let i = Math.min(arr[0], arr[1]); i <= Math.max(arr[0], arr[1]); i++) {
newArr.unshift(i);
}
let answer = newArr[0] * newArr[1];
for (let i = 2; i < newArr.length; i++) {
if (answer % newArr[i] == 0) {
} else {
answer *= newArr[i]
}
}
return answer;
}
smallestCommons([1,5]);
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Challenge: Smallest Common Multiple
Link to the challenge: