Solution for Rosetta Code: Iterated digits squaring

Contributors
1

What is your hint or solution suggestion?
Split into integer array. Square using Array.map and add all integers. if(sum == 89|sum == 1), return answer, otherwise, return iteratedSquare(sum), which creates a recursive function.

Solution 1 
function iteratedSquare(n) {
    var result = Array.from(n.toString()).map(Number).map(x => x ** 2);
    var sum = result.reduce((a, b)=> a + b, 0);
    if(sum == 89|sum == 1){
      return sum;
    }
    else{
      return iteratedSquare(sum)  
    }
}

Challenge: Iterated digits squaring

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