[solved] Basic Algorithm Scripting: Slice and Splice, Assigning Splice to a variable

1

Why assigning Splice to a variable doesn’t work?

See commented line at bottom of code:
return arr2Mod passes all tests, but return newArray doesn’t. Why can’t I assign Splice to a variable?

My code:

function frankenSplice(arr1, arr2, n) {
  // It's alive. It's alive!
  let arr1Mod = [...arr1];
  let arr2Mod = [...arr2];
  let newArray = [];
  for (let i = 0; i < arr1.length; i++) {  
    let newArray = arr2Mod.splice(n, 0, arr1Mod[i]);
    ++n;
  }

  return newArray;
 //  return arr2Mod;
}
2

I’m not sure what the intended result of frankenSplice is (it’s been a long time since I’ve done that challenge) but one problem I see immediately is that you’re reassigning newArray for every iteration through the loop. Perhaps you intended to .push to newArray instead?

3

Thanks a lot for reverting @chuckadams
Humm, unsure if that is what is making it not work. Let me provide another example:

The below works:

// var fruits = ["Banana", "Orange", "Apple", "Mango"];
// console.log(fruits);

// function myFunction() {
//   fruits.splice(1, 0, "Lemon", "Kiwi");
//   return fruits;
// }

// myFunction();

However, when assigning Splice to a variable, it doesn’t work. I’m trying to understand why here. :slight_smile:

// var fruits = ["Banana", "Orange", "Apple", "Mango"];
// console.log(fruits);

// function myFunction() {
//   let fruta = fruits.splice(1, 0, "Lemon", "Kiwi");
//   return fruta;
// }

// myFunction();
4

Because you’re returning two different things. In the first, you’re returning the array that had a chunk spliced out of it (fruits), and in the second you’re returning the chunk that was spliced out of the array (fruta).

1 Like
5

Oh, I should have read MDN’s examples before asking. :zipper_mouth_face:

Thanks a ton for the clarification @chuckadams

6