[Solved] Return Largest Numbers in Arrays Solved but Doesn't Pass

1

Hi all,

This is my first post. I’ve met the requirements to pass the challenge below, but for some reason, it won’t recognize it as a legitimate answer. I’m hoping someone could point out something simple I’ve overlooked or confirm that this is some kind of glitch.

var finalArray=[];
function largestOfFour(arr) {
  for (var i = 0; i < arr.length; i ++) {
   finalArray.push(Math.max.apply(null, arr[i]));   
} 
return finalArray;
}
2

When running your code on the 2nd test case I get: [5, 27, 39, 1001, 27, 5, 39, 1001].

When running on the 3rd test case I get: [5, 27, 39, 1001, 27, 5, 39, 1001, 9, 35, 97, 1000000].

1 Like
3

Thanks for checking it out.

When i run it in the console, i always get a bunch of added numbers like that.

Was this from the console or the FCC return screen? In the console I get the numbers you say, but in the return screen, I get what I’m supposed to. I’ve passed previous challenges this way.

4

It was in the console. Not to sure why it’s worked in the past, maybe its caught up with you :grin:?

5

don’t declare the global variable in fcc challenge
cause fcc run 3 test at first test your global variable finalArray=[] is empty but after first test it is no longer empty
[]
[5, 27, 39, 1001]
[5, 27, 39, 1001, 5, 27, 39, 1001]
[5, 27, 39, 1001, 5, 27, 39, 1001, 27, 5, 39, 1001]

To avoid this, just call that global variable finalArray=[] inside your
largestOfFour function

1 Like
6

Haha. Maybe so.

But I’ve read the FCC site runs other stuff in the background that interferes. Others have also said they notice their test running 2-3 times on udemy too.

This goes to show in a way then it’s good practice to declare temp variables inside a function.
May I ask which browser you are using to complete the exercises?

Anyway, thanks for feedback!

7

Awesome. Cut and Paste!

And thanks for confirming the 3-run test.

I initially moved it out cause I couldn’t push to it when using other methods.
Instead of pushing I was hoping I could just return Math.max.apply(null, arr[i]) as an array, but it would just return null.

8

It was a quick fix. Here’s my solution. Time to check out other solutions and compare! Thanks @mones-cse

function largestOfFour(arr) {
  var finalArray=[];
  for (var i = 0; i < arr.length; i ++) {
   finalArray.push(Math.max.apply(null, arr[i]));   
} 
return finalArray;
}