Spinal Tap - For Loop Execution Question for Non Regex Solution

Spinal Tap - For Loop Execution Question for Non Regex Solution


Hi there, I’m trying to solve this algorithm without using any regex. What I would like to do is something like this:

function spinalCase(str) {
  var arr = str.split('');

  for (var i = 0;  i < arr.length - 1; i++){
    //if the char is a " " or "_" replace with "-" 
    if (arr[i] === " " || arr[i] === "_"){
      arr[i] = "-";
    } else {
      //otherwise, check if the next char is upper and the current char is lower,
     //if true splice appropriately
      if (isUpper(arr[i+1]) && isLower(arr[i])){
        arr.splice(i+1, 0, "-");
  return arr.join('').toLowerCase();

function isUpper(x){
  return x === x.toUpperCase();

function isLower(x){
  return x === x.toLowerCase();

spinalCase('AllThe-small Things');

When I try to run this code I actually get an infinite loop warning and the program will not run. I’m not sure why this is so if someone could explain that would be gret. Is this because I am changing the length of the array during the loop? When the loop is first executed and arr.length - 1 is calculated is it a fixed value for the duration of the entire loop? Or is it recalculated with every iteration?

Thank you everyone


@Swoodend, since you’re splicing with a delete count of 0, it’s constantly increasing the length of arr.
So your i variable will never reach the end of your array.


is there a reason you’re not using RegEx?
The code is very short and simple with it…


Hm. Could you explain why it will not reach the end of the loop. I understand that I am increasing the length off arr, but isn’t the stop condition (arr.length -1) in the for loop tested every iteration?

For instance, if I increase the length of arr by 3, wont (arr.length - 1) also increase by 3, and, instead of being an infinite loop it will just iterate 3 more times? I dont understand why this isn’t the case.



let say the string is “HelloWorld”.

at the iteration where i = 4, your if condition will evaluate to true for upper and lower, so it will insert “-”.

at the next iteration (i = 5)…
isUpper(arr[6]) = true (W)
isLower(arr[5]) = true (-)

resulting in “Hello–World”

next iteration would result in "Hello—World"
Then “Hello----World”…

wash, rinse, repeat…


Thanks 8-up!

That makes sense I didn’t know and did not test that isLower("-") returns TRUE! I thought that punctuation would return undefined or something falsey.

Really appreciate the help. I’m not sure why I chose to not use regex, I think this is just what I started writing and I wanted to stick with it.

Thanks again.