Spread operator function

JavaScript
1 
const arr1 = ['JAN', 'FEB', 'MAR', 'APR', 'MAY'];

let arr2;

(function() {

"use strict";

arr2 = []; // change this line

})();

console.log(arr2);

what does the () at the end of the function execute. what is its importance

2

It allows the function to be an IIFE (Immediately Invoked Function Expression). This will cause the function to execute as soon as it is read. you can think of it as:

function nameOfFunction() {

“use strict”;

arr2 = ; // change this line
}

nameOfFuntion() //this does the same thing but you give it a name and execute it on a different line
3

I’ve edited your post for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

See this post to find the backtick on your keyboard. The “preformatted text” tool in the editor (</>) will also add backticks around text.

Note: Backticks are not single quotes.

markdown_Forums

4

Thanks bro,for your prompt reply
Respect